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Ray Of Light [21]
3 years ago
9

Which of these is an example of a literal equation?

Mathematics
1 answer:
guapka [62]3 years ago
3 0
Im pretty sure it’s A
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Suppose u=<2,−1> and v=<1,−8> are two vectors that form the sides of a parallelogram. Then the lengths of the two di
tigry1 [53]
| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
 (2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
8 0
3 years ago
A: Half of a 16 inch pizza or pizza B: A whole 10 inch pizza to himself. Which pizza would ensure him the largest amount?
harkovskaia [24]

Answer:

Choice B, 10 inch pizza to himself

Step-by-step explanation:

1. Half of 16 inch pizza= 8 inch

2. 10 inch pizza to himself= well, 10 inch

10>8

7 0
3 years ago
Read 2 more answers
Find the sum of the following ap .1) 1/15, 1/12, 1/10,....,to 11 terms​
sertanlavr [38]

Answer:

33/20

Step-by-step explanation:

1/12 - 1/15 = 5/60 - 4/60 = 1/60

d = 1/60

a_n = a_1 + d(n - 1)

a_11 = 1/15 + (1/60)(11 - 1)

a_11 = 1/15 + 1/6

a_11 = 4/60 + 10/60

a_11 = 14/60

a_11 = 7/30

a_12 = 14/60 + 1/60

a_12 = 15/60

a_12 = 1/4

s_n = n(a_1 + a_n)/2

s_11 = 11(1/15 + 7/30)/2

s_11 = 11(2/30 + 7/30)/2

s_11 = 11(9/30)/2

s_11 = 99/60

s_11 = 33/20

8 0
3 years ago
Please help thank you so so so much <br><br> there is more than one answer
Luden [163]

Answer:

B and C work. A and D do not.

Step-by-step explanation:

This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.

A]

5n + 6

Let n = 1

5(1) + 6

5 + 6= 11

However there is trouble beginning with n = 2

5*2 + 6

10 + 6

16     All you need is one wrong answer and the choice is toast. So A won't work.

================

Try D

6(n - 1)+ 5

n=0

6*(-1) + 5

-6 + 5

- 1

And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse.  D is not one of the answers.

=============

B

Let n = 1

6(1) + 5

6 + 5

11 The first term works.

n = 2

6*(2) + 5

12 + 5

17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.

n = 3

6*(3) + 5

18 + 5

23 And this also works. I'll let you deal with n = 4

========

C

n = 0

6(0 + 1) + 5

6*1 + 5

6 + 5

11

n = 1

6(1 + 1) + 5

6*2 + 5

12 + 5

17 which works.

So C is an answer.

4 0
3 years ago
Please help i am confused
son4ous [18]

Answer: (4)

Step-by-step explanation:

The parts listed in the congruence statements don't correspond, so they aren't necessarily congruent.

7 0
2 years ago
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