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3 years ago

A commercial package contains thirty-six 200-mg tablets of ibuprofen. How many kilograms of ibuprofen were

Mathematics

1 answer:

PIT_PIT [208]3 years ago

3 0

Answer: 0.0072 kilogram

Step-by-step explanation:

Given : The mass of one tablet of ibuprofen =200 mg

Then, the mass of 36 tablets of ibuprofen = $36\times200$ mg

i.e. the mass of 36 tablets of ibuprofen = $7200$ mg

We know that 1 kilogram = 1000 grams

and 1 gram = 1000 milligram

Then, 1 kilogram = $1000,000$ milligrams

Then, $\text{1 mg}=\dfrac{1}{1000,000}\text{ kg}$

Now, $\text{7200 mg}=\dfrac{7200}{1000,000}=0.0072\text{ kg}$

Hence, A commercial package contains 0.0072 kilogram of ibuprofen.

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Find r(7) for the function r(n)=0.009n

Savatey [412]

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3 years ago

A substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 a

ella [17]

Answer:

We conclude that the reaction time is increased or remains same by frequent alcohol use.

Step-by-step explanation:

We are given that a substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 alcoholics and finds that their mean reaction time (in ms) to a stimulus equals 283.

Reaction times to the stimulus in the general population are distributed normally with a mean equal to 281 and a standard deviation equal to 28.

Let $\mu$ = mean reaction time after alcohol use.

So, Null Hypothesis, $H_0$ : $\mu$ $\geq$ 281 {means that the reaction time is increased or remains same by frequent alcohol use}

Alternate Hypothesis, $H_A$ : $\mu$ < 281 {means that the reaction time is decreased by frequent alcohol use}

The test statistics that would be used here One-sample z test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}$ ~ N(0,1)

where, $\bar X$ = sample mean reaction time (in ms) = 283

$\sigma$ = population standard deviation = 28

n = sample of alcoholics = 164

So, test statistics = $\frac{283-281}{\frac{28}{\sqrt{164}}}$

= 0.915

The value of z test statistics is 0.915.

Now, at 0.01 significance level the z table gives critical value of -2.3263 for left-tailed test. Since our test statistics is more than the critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the reaction time is increased or remains same by frequent alcohol use.

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3 years ago

Meg makes a dot plot for the data 9, 9, 4, 5, 5, 3, 4,5, 3, 8, 8, 5. Where does a gap occur?

Papessa [141]

The gap consists of the values 6 and 7.

Check out the dot plot below to see what I mean. We have one cluster on the left from 3 to 5. Then another cluster on the right from 8 to 9.