Answer:
I. m = 2401
II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]
Step-by-step explanation:
I. Determination of m
x ∆ y = x² − 2xy + y²
2 ∆ − 5 = √m
2² − 2(2 × –5) + (–5)² = √m
4 – 2(–10) + 25 = √m
4 + 20 + 25 = √m
49 = √m
Take the square of both side
49² = m
2401 = m
m = 2401
II. Simplify ((n+1) ∆ y)/n
We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:
x ∆ y = x² − 2xy + y²
(n+1) ∆ y = (n+1)² – 2(n+1)y + y²
(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²
(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1
(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1
(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1
(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1
(n+1) ∆ y = (n – y + 2)(n – y) + 1
((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n
((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]
Answer:
-4x^2 + 237x - 675
Step-by-step explanation:
(x - 3)*(232 - 4x -7) >> Distribute x and -3 to the trinomial
232x - 4x^2 - 7x - 696 + 12x + 21 >> Simplify
-4x^2 + 237x - 675
Answer:
0,-3
Step-by-step explanation:
because its across it so it probbly dose not cam o it dose poloyn it
Answer:
In every 42 days, Sherman and Brad will go golfing on the same day.
Step-by-step explanation:
Given:
Sherman goes golfing every 6th day.
Brad goes golfing every 7th day.
If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.
Solution:
In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.
To find least common multiple of 6 and 7, we will list out their multiples.
We find out that the least common multiple of 6 and 7 =42.
Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..
