3 years ago

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Mathematics

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Reil [10]3 years ago

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Deffense [45]

Consider the fraction $\dfrac{k+7}{4k+28}$ .

1. You can see that the denominator 4k+28 can be simplified to expression 4(k+7), because 4k=4·k and 28=4·7, so using the distributive property you can write that 4k+28=4(k+7).

2. Then the initial fraction becomes

$\dfrac{k+7}{4k+28}= \dfrac{k+7}{4(k+7)}$ .

3. The nominator and the denominator have the common divisor k+7, then you can divide top and bottom by k+7:

$\dfrac{k+7}{4k+28}= \dfrac{k+7}{4(k+7)}=\dfrac{1}{4}$ .

Answer: $\dfrac{1}{4}$