Answer:
y = |x - 1|
Step-by-step explanation:
You should recognize that subtracting the x term should translate the graph to the right
Answer:
The Proof is given below.
Step-by-step explanation:
Given:
P is the center of Circle
∠ONE ≅ ∠TEN
To Prove:
∠5 ≅ ∠6
Proof:
Exterior Angle Theorem:
Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.
STATEMENT REASON
1. So In ΔONE,
1. Exterior Angle Property of a Triangle.
2. Similarly In ΔTEN,
2. Exterior Angle Property of a Triangle.
3. But , ∠ONE ≅ ∠TEN 3. Given
4. And P is the center of circle So
4.radius of same circle
5. ΔPEN is an Isosceles triangle,
∴ ∠ 1 ≅ ∠ 2 5. Isosceles triangle property
6. ∴ ∠5 ≅ ∠6 6. From 3 and 5 Transitive Property.........Proved
Answer:
Option A: P ≈ 38.7 in, A ≈ 63.7 in²
Step-by-step explanation:
We are told that △MNO ~△DEF. This means that they are similar triangles.
We can solve for this using scale factor.
a) Perimeter of △MNO
The scale factor of two similar triangles is equal to the ratio of the perimeter of the triangles
Scale factor(k) = ratio of the sides of the triangles
In the diagram we are given
Side of △MNO = 6.7in
Side of △DEF = 9in
Perimeter of △MNO = X
Perimeter of △DEF = 52in
Scale factor (k) = 6.7/9
Hence,
6.7/ 9 = X/52
Cross Multiply
9X = 6.7 × 52
X = 6.7 × 52/9
X = 38.711111111 inches
To the nearest tenth, Perimeter of △MNO = 38.7 inches
b) Area of △MNO
The square of the scale factor of two similar triangles is equal to the ratio of area of the triangles
Scale factor(k) = ratio of the sides of the triangles
In the diagram we are given
Side of △MNO = 6.7in
Side of △DEF = 9in
Area of △MNO = Y
Area of △DEF = 115in²
Scale factor (k) = 6.7/9
Hence,
(6.7/ 9)² = Y/115
6.7²/9² = Y / 115
Cross Multiply
9² × Y = 6.7² × 115
Y = 6.7²× 115 /9²
Y = 63.732716049 square inches
To the nearest tenth, Area of △MNO = 63.7 in²
Answer:
2,176,782,336
Step-by-step explanation:
Just asked a friend -.-
The answer should be D) 22/25.
