Question

-5/3 is a root of f(x) = (3x + 5) (x2 - 6x + 9)2 = 0 True False

Answer 1

False...................

Answer 2

For this case we have the following function:

$f (x) = (3x + 5) (x ^ 2-6x + 9) ^ 2$

To find the roots we must equal the function to 0, that is:

$(3x + 5) (x ^ 2-6x + 9) ^ 2 = 0$

So:

$3x + 5 = 0$

Subtracting 5 from both sides:

$3x = -5$

Dividing between 3 on both sides:

$x = - \frac {5} {3}$

Thus, one of the roots is $x = - \frac {5} {3}$

Answer:

True