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natita [175]
3 years ago
15

Suppose the amounts of M&M's a machine dispenses into packages has a normal distribution with a mean of 25 M&M's and a s

tandard deviation of 1 M&M. What is the probability that there are more than 26 M&M's?

Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

16%

Step-by-step explanation:

The mean is 25, and the standard deviation is 1.

26 is 1 standard deviation above the mean.

According to the empirical rule, 68% of the population is between -1 and +1 standard deviations.  That means that 32% is less than -1 or greater than +1 standard deviations.  So half of that, or 16%, is greater than +1 standard deviations.

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The measure of the supplement of an angle is 42 more than 3 times the measure of the complement of an angle. Find the measure of
Novosadov [1.4K]

Answer:

126

Step-by-step explanation:

We multiply 42 × 3= 126

The measure of the angle is 126.

8 0
3 years ago
the vertex of this parabola is at (-2,-3). When the x. value is -1and the y value is -5, what is the coefficient of the squared
musickatia [10]
Yes✨! The answer is deletus tweetus hocus pokus strolls! (Sorry I really need points)
3 0
3 years ago
Find the value of this expression if x = 3<br> and y = -1.<br> xy²<br> 5
kap26 [50]

Answer:

<h2><em><u>0.6 = 6/10 = 3/5 is the answer.</u></em></h2>

Step-by-step explanation:

0.6 = 6/10 = 3/5

is the answer

This is because you have to substitute.

Given:

x = 3

y = -1

Unknown:

Final Answer

(x*y^2)/5

((3)(-1*-1)/5

= (3*1)/5

<h2><em><u>= 3/5</u></em></h2><h2><em><u>= 6/10</u></em></h2><h2><em><u>= 0.6</u></em></h2><h2><em><u></u></em></h2>

Hope this helped,

Kavitha

6 0
4 years ago
Can you help me find the answer .Will mark brainliest
ahrayia [7]

Answer:

do R-P-R-S-P-P-R-P

Step-by-step explanation:

4 0
3 years ago
The equation $a^7xy-a^6y-a^5x=a^4(b^4-1)$ is equivalent to the equation $(a^mx-a^n)(a^py-a^2)=a^4b^4$ for some integers $m$, $n$
Ksivusya [100]
Let <span>simplify the equations a^7xy-a^6y-a^5x=a^4(b^4-1) and (a^mx-a^n)(a^py-a^2)=a^4b^4:
</span>
<span>1) a^7xy-a^6y-a^5x+a^4=a^4b^4
</span>
<span>and
</span>
<span>2) a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4.
</span>
<span>Equate the coefficients:
</span><span>
</span><span>xy: m+p=7  \\ y: n+p=6 \\ x:  m+2=5 \\ 1: n+2=4.</span>
Then n=2 \\ p=4 \\ m=3 and mnp=24.
<span />
3 0
3 years ago
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