You can solve all of these by using the distance formula. I have shared it below.
List all the different combinations with total cost:
Airplane + van = 350 + 60 = $410
Airplane + cab = 350 + 40 = $390
Bus + van = 150 + 60 = $210
Bus + cab = 150 + 40 = $190
Train + van = 225 + 60 = $285
Train + cab = 225 + 40 = $265
There are 6 different combinations.
There are 2 that are more than $300
The probability would be quantity higher than 300 / total combinations.
Probability = 2/6 = 1/3
Answer:
EF = 
≈ 5.83
Step-by-step explanation:
Calculate EF using the distance formula
d = 
with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)
EF = 
= 
= 
= ≈ 5.83 ( to 2 dec. places )
I havnt done that in a while but I think you do x+105=x+95 then you add your like terms which would turn into 10=2x then you divide 10 divided by 2 which is 5, SO YOUR ANSWER IS (I think) 5x
Answer:
1 : 4 , 1 : 4
Step-by-step explanation:
= 3 : 12 , 48 : 192
= 3/12 , 48/192
= 1/4 , 1/4
= 1 : 4 , 1 : 4
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