Answer:
The original price is $650
Step-by-step explanation:
There's an actual algebra method for this, but this is my method because I find it way easier to remember.
Since the most you can discount out of an item is 100% (well, it's considered free then) let's subtract 100 - 34, which is 66.
Now, turn it into a decimal because it makes the numbers easier- 0.66.
Since when you're finding the discount of an original price, you multiply the original price by the discount- instead for finding the original price for a discounted item we divide $429 by 0.66 instead, since when you divide a number by another number that's under 1 the quotient is a larger number.
So, 429 ÷ 0.66 = 650.
Therefore, the original price of the $429 sale price for a 34% discount is $650.
Length of rectangle is 1 unit
<u>Solution:
</u>
Given that
Length of a rectangle is width minus 8 units.
Area of rectangle = 9 square units
Need to calculate the length of rectangle.
Let us assume width of rectangle = x
As Length is width minus 8,
Length of the rectangle = x – 8



As given that area of rectangle = 9 square units

On solving above quadratic equation for x, we get

When 
When
As width cannot be negative, so considering x = 9

Hence, Length of rectangle is 1 unit.
Step-by-step explanation:
7+2x-2 = 4x -3
5= 2x -3
2x = 8
x = 4
Answer:
E. Deep venous thrombosis
Step-by-step explanation:
According to a different source, these are the options that come with this question:
A. Depression
B. Smoking history
C. Severe nausea on combined oral contraceptives
D. Lactation history
E. Deep venous thrombosis
This woman would be a good candidate for the progestin-only pill because of her deep venous thrombosis, as contraindications to estrogen include a history of thromboembolic disease. Other contraindications include women who are lactating, women over 35 who smoke or women that have experienced severe nausea when using combined pills.
Answer:

Step-by-step explanation:
we know that
The area of the figure is equal to the area of rectangle plus the area of two semicircles
<u>The area of rectangle is equal to</u>

<u>The area of the small semicircle is equal to</u>

-----> radius is half the diameter
substitute

<u>The area of the larger semicircle is equal to</u>

-----> radius is half the diameter
substitute

The area of the figure is equal to
