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Natasha_Volkova [10]

3 years ago

11

the formula for the area of a square s to the 2nd power, where s is the side length of the square. What is the area of a square

with a side length of 6 centimeters? Do not include units in your answer

1 answer:

Helen [10]3 years ago

5 0

The answer to this is 36.

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Val’s go cart has a gas tank with the dimensions shown below. He uses a gas can that holds 1 gallon of gas, to fill the go cart

SOVA2 [1]

$v = bh$

$v = (15.4 \times 10) \times 3$

$v = {462} \: inches \: ^{3}$

~~

$462 \div 231 = 2$

~~

It will take 2 full gas cans to fill it up!!

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

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D= 90* AC=17 cm AD=10 cm CD=?cm<br><br> please in need help in this

padilas [110]

Answer:

Step-by-step explanation:Idon't say u must have ro mark my ans as brainliest but if u think it has really helped u plz don't forget to thank me....

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True or false, rotational symmetry is the quality a design has if it maintains all characteristics when it is rotated about a po

Andru [333]

<h2>True.</h2><h2 />

In fact, if a design still looks the same after some rotation, then it has Rotational Symmetry. In this context, this design can be an object, a figure, a thing, etc. So these characteristics is the typical quality or feature of this object, figure or thing. An example of rotational symmetry is the Ferris Wheel when it rotates about the center.

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To solve: x + 8 = 40

Scorpion4ik [409]

Well, to solve, you would subtract 8 from both sides, which means x would end up equaling 32.

X=32

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An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y

Kay [80]

Answer:

$t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28$

Now we can calculate the p value with the following probability:

$p_v =2*P(t_{60}$

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

$\bar X_{1}=14$ represent the mean for sample 1 (younger)

$\bar X_{2}=20$ represent the mean for sample 2 (older)

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=31$ sample size for the group 2

$n_{2}=31$ sample size for the group 2

t would represent the statistic

System of hypothesis

We want to test if that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

The statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=31+31-2=60$

Replacing the info given we got:

$t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28$

Now we can calculate the p value with the following probability:

$p_v =2*P(t_{60}$

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0

3 years ago