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3 years ago

What are the slope and the y-intercept of the graph of the linear function shown on the grid?

Mathematics

1 answer:

poizon [28]3 years ago

8 0

Y-intercept looks like -1.5 and slope is -1/4

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The total current of a parallel circuit is 9+j2 amps and the current of one component of the circuit is 3−j5 amps. What is the c

stealth61 [152]

Apply law of total resistance in parallel circuit

$\\ \tt\hookrightarrow \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\\ \tt\hookrightarrow \dfrac{1}{9+2J}=\dfrac{1}{3-5j}+\dfrac{1}{R_2}$

$\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{1}{9+2J}-\dfrac{1}{3-5J}$

$\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{3-5J-9-2J}{(9+2J)(3-5J)}$

$\\ \tt\hookrightarrow R_2=\dfrac{(9+2J)(3-5J)}{-6-7J}$

4 0

2 years ago

What is the equation for the line that goes through points (3,6) and (-3,-2)?

Basile [38]

Unless unusually unusual unification under

5 0

2 years ago

I NEED MATH HELP ASAP!

gizmo_the_mogwai [7]

P + t = 140
t = p - 4 or p - t = 4

answer is A first one

4 0

3 years ago

If you earn $48,000 per year, how much will you receive on a biweekly basis?

Harrizon [31]

$48,000 a year is $1,846.15 biweekly before taxes and approximately $1,384.62 after taxes. Paying a tax rate of around 25% and working full-time at 40 hours a week, you would earn $1,384.62 after taxes. To calculate how much you make biweekly before taxes, you would multiply $23.08 by 40 hours and 2 weeks

5 0

2 years ago

Read 2 more answers

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean $(\mu)$ = 500 and a standard deviation $(\sigma)$ = 100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = $\dfrac{Y-\mu}{\sigma}$

Z-score = $\dfrac{625-500}{100}$

⇒ Z-score = $\dfrac{125}{100}$

⇒Z-score =1.25

Therefore , the required z-score = 1.25

6 0

3 years ago