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DaniilM [7]
3 years ago
14

Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4.

x + 11 = 2 Superscript 4. x + 11 = 16. x = 5. x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 2 x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 4 x = 5 is a true solution because log Subscript 2 Baseline (16) = 4 x = 5 is a true solution because log Subscript 4 Baseline (16) = 2
Mathematics
1 answer:
meriva3 years ago
5 0

Answer:

Option C.

Step-by-step explanation:

The given logarithmic equation is

\log_2(x+11)=4

It can be written as

(x+11)=2^4     [\because log_ax=y\Leftrightarrow x=a^y]

x+11=16

x=5

Now, to check whether x=5 is a true solution or not. Substitute x=5 in the LHS of given equation.

LHS=\log_2(5+11)

LHS=\log_2(16)

LHS=\log_22^4

LHS=4     [\because log_aa^x=x]

LHS=RHS

Hence, x=5 is a true solution because \log_2(16)=4.

Therefore, the correct option is C.

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The points (2, 5) and (6,-3) fall on a particular line. What is its equation in slope-intercept form?
Pachacha [2.7K]

Answer:

y = -2x + 9

Step-by-step explanation:

slope intercept form : y = mx + b

where m = slope and b = y intercept

first let's find the slope

slope formula :

m = ( \frac{y2 - y1}{x2 - x1} )

where the x and y values are derived from the given points

here we are given (2,5) and (6,-3)

(x1,y1) = (2,5) so x1 = 2 and y1 = 5

(x2,y2) = (6,-3) so x2 = 6 and y2 = -3

we now plug these values into the formula

recall formula

m= ( \frac{y2 - y1}{x2 - x1} )

plug in x1 = 2, y1 = 5, x2 = 6 and y2 = -3

m = (-3 - 5) / ( 6 - 2 )

m = (-8)/(4)

m = -2

the slope is -2

now to find the y intercept we plug in the slope and the x and y value of a given point into slope intercept form and solve for b

y = mx + b

given point : (2,5) x = 2 , y = 5, m = -2

5 = -2(2) + b

5 = -4 + b

9 = b

so the equation would be y = -2x + 9

6 0
3 years ago
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