<span>assume z = ax for simplicity
z(z) = a(ax) = a^2x
let a^2x = 1/16x and solve for a </span>
Answer:
11
Step-by-step explanation:
since 30÷45 = 2/3 then
The space taken by a small book is equal to
the space taken by 2/3 a large book.
…………………………………………………
<u><em>Calculating the number of large book corresponding to 23 small books</em></u> :
= 23×(2÷3) + 3
= 18.333333333333 (large book)
Then ,Kevin can pack the shelf with (at most) : 30 - 19 = 11 more large books
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer:
6x^3y^2+18x^4y^3+18x^2y^5
Step-by-step explanation:
Multiply each term:
6x^3y^2+18x^4y^3+18x^2y^5
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