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4 years ago

What is the Factor X2 -36 -40

Mathematics

1 answer:

Leya [2.2K]4 years ago

8 0

Answer:x^2-76

Step-by-step explanation:

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Use the Distance Formula to write an equation of the parabola with focus F (0, 4) and directrix y = -4.

alexdok [17]

Step-by-step explanation:

focus=(0,4)

Direcrtrix,y=-4

p=4

vertex=(0,0)

Open upward

(x-h)²=4p(y-k)

(x-0)²=4(4)(y-0)

(x-0)²=16(y-0)

8 0

4 years ago

Porter drove due east 20 miles on interstate 23 then due south on interstate 77 to the nearest hundredth of a mile how far was h

OverLord2011 [107]

Answer:

30.48 miles

Step-by-step explanation:

This can be represented as a right angle triangle with sides 20 miles and 23 miles. The hypotenuse is the distance from the starting point. Pythagoras theorem states that for a right-angled triangle, the square of side of the hypotenuse is equal to the sum of squares of the other two sides. It is given by the equation:

c² = a² + b², where c is the hypotenuse and a,b are the sides

Let a = 20 miles and b = 23 miles

c² = a² + b²

c² = 20² + 23²

c² = 400 + 529

c² = 929

c = √929 = 30.48

c = 30.48 miles

7 0

4 years ago

Last week, the price of almonds was $8.95 per pound. This week, almonds at the same store were on sale at a 15% discount. What i

aalyn [17]

Answer:

$19.02

Step-by-step explanation:

15% of 8.95 = 1.3425

one pound = 8.95 = 1.34 = 7. 61

half a pound = 3.805

7.61 + 7.61 + 3.8 = 19.02

3 0

3 years ago

Yepa is solving 1.6 ÷ 6.4.

Softa [21]

Answer:

1/4=0.25

Step-by-step explanation:

4 0

3 years ago

A quadrilateral has vertices A, B, C, and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units

Kryger [21]

Answer:

The correct option is O B'

Step-by-step explanation:

We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.

Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.

In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.

Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).

I will attach a drawing with an example.

Finally, we only have to look at the vertices and its original distances to answer the question.

The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'

8 0

3 years ago