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mixas84 [53]
4 years ago
6

What is 3x-4y=4 in linear equations

Mathematics
2 answers:
KengaRu [80]4 years ago
7 0
Your equation is a linear equation because it has a constant, and it has variables. And it does not have something like x^2.

However, if your question wants it in slope-intercept format, which is y=mx+b

Then:

3x-4y = 4

We can add 4y to both sides
3x = 4+4y

Subtract 4 from both sides
3x-4 = 4y

Then we divide by 4
\frac{3}{4} x -1=y

So 3x-4y=4 in slope-intercept format would be y =\frac{3}{4} x -1
Lostsunrise [7]4 years ago
6 0
I hope this was helpful to you thnx

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The product of the slopes of perpendicular lines is −1. Which function represents a line that is perpendicular to y = −6x + 7?
neonofarm [45]
The perpendicular line to y = -6x + 7 will have a slope that is the reciprocal of the slope of this line with the sign flipped to the opposite so if the slope is m = -6 for this, this the perpendicular line will have a slope of m = 1 / 6.
Any line with the form y = (1/6)x + b will be perpendicular
8 0
4 years ago
Read 2 more answers
the diameter of a bicycle wheel is 0.7 meters. find the number of complete revolutions made by the wheel if the bicycle travels
larisa [96]

Answer:

200\ rev

Step-by-step explanation:

we know that

1\ rev=2\pi r ----> circumference of a circle

step 1

Find the circumference of a circle

The circumference is equal to

C=2\pi r

we have

r=0.7/2=0.35\ m ----> the radius is half the diameter

\pi=22/7

substitute

C=2(22/7)(0.35)=2.2\ m

step 2

Find the number of complete revolutions made by the wheel if the bicycle travels 440 meters

Divide the total distance by the circumference

\frac{440}{2.2}=200\ rev

7 0
3 years ago
Consider the function f(x) = x2 + 2x – 15. What are the x-intercepts of the function?
Rus_ich [418]

Answer:

The x-intercepts of the function are x = 3 and x = -5.

Step-by-step explanation:

We are given the function \displaystyle f(x) = x^2 + 2x - 15.

In order to find the x-intercepts of the equation, we need to solve this quadratic. We can use factoring methods to solve it.

The parent function for a quadratic is f(x) = ax^2 + bx + c = 0.

We can use this information to determine what factoring technique we want to use.

There are several different methods, including using the quadratic formula, but because this is easily factorable, we can avoid using it.

We see that our <em>a</em> is equal to 1 (there is no coefficient in front of x²), so we can use the easier of the techniques:

  • Find what factors of c add up to give you b.
  • Add to x if positive or subtract from x if negative and set it equal to zero.
  • Solve for x - these are your x-intercepts.

Therefore, let's determine what our c is: 15.

Now, let's label the factors for 15.

  • 15 cannot be divided by 2 evenly.
  • 15 can be divided by 3 evenly: 15/3 = 5
  • 15 cannot be divided by 4 evenly.
  • 15 can be divided by 5 evenly: 15/5 = 3

Therefore, our two factors are 3 and 5 since they cannot be broken down any further (they are prime numbers - we just performed prime factorization).

Now, we need to pay attention to the sign for c. It's negative, so one of our factors needs to be negative. Therefore, we can test this out:

  • 5 + -3 = 2
  • -5 + 3 = -2

Now, we check for which one matches the sign for b. This is positive 2, so our two factors are 5 and -3.

Finally, to factor, we add or subtract the factors from x depending on the sign. If the factor is positive, we add it. If the factor is negative, we subtract it. Therefore, we can set up our equations.

x + 5 = 0\\\\x = -5

x - 3 = 0\\\\x = 3

Therefore, for when x = 3 or x = -5, the line crosses the x-axis. These are the x-intercepts of the function.

Our answers are x = -5 and x = 3.

4 0
3 years ago
Reduce 36/45 to lowest terms and write the numerator in the blank.
saveliy_v [14]
4/5 is your answer

Hope this helps
7 0
4 years ago
Read 2 more answers
What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
4 0
3 years ago
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