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3 years ago

Simplify. Remove all perfect squares from inside the square ✓75yz

Mathematics

1 answer:

JulijaS [17]3 years ago

7 0

Answer:

From this term $\sqrt{75yz}$ , we cannot remove variable as they are not in square form .

Thus we look at number 75

75 = 25 × 3

25 is a perfect square , so it can come out and this we get 5 when its removed

Thus the answer is $5\sqrt{3yz}$

I hope it helps you

#Indian : )

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For triangle xyz , the measures of angles x,y, and Z are known. Which method should be used to start solving triangle xyz?

Kisachek [45]

Neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used

<h3>Solving trianngles using the laws of sines & cosines </h3>

The law of sines is written as

$\frac{sinA}{a}=\frac{sinB}{b}= \frac{sinC}{c}$

Where a,b, and c are sides of any given triangle and A,B, and C are the angles.

This law is used when we are given either

Two angles and one side, or
Two sides and a non-included angle

The law of cosines is written as

a² = b² + c² -2bc cosA, or

b² = a² + c² - 2ac cosB, or

c² = a² + b² -2ab cosC

Where a,b, and c are sides of any given triangle and A,B, and C are the angles.

This law is used when we are given either

Three sides or
Two sides and the included angle

Now, for triangle xyz, which the measures of angles X,Y, and Z are known, neither law can be used to solve the triangle.

Hence, neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used

Learn more on Solving triangles using the laws of sines & cosines here: brainly.com/question/22339733

5 0

3 years ago

BRAINLIEST!!

Nesterboy [21]

Answer:

74.5%

Step-by-step explanation:

The total number of people sampled is 1000 people.

There are 745 people who where corrective lenses.

Percent is (part)/(whole); in this case, the part is 745 and the whole is 1000, so:

745/1000 = 74.5%

Thus, the answer is 74.5%.

Hope this helps!

7 0

3 years ago

Read 2 more answers

A chemical company makes two brands of antifreeze. The first brand is 55 % pure antifreeze, and the second brand is 80 % pure an

Likurg_2 [28]

We have 55% and 80% antifreeze. We need 90 gallons of 75%.

F - 55% and E - 80%

A) F + E = 90

B) .55 F + .80 E = 67.50 (which is .75 * 90) Multiplying A) by -.55

A) -.55 F -.55 E = -49.50 (which is -.55 * 90) then adding A) & B)

.25 E = 18

E = 72 gallons of 80% and

F = 18 gallons of 55%

********* DOUBLE CHECK ******************

72 * .80 = 57.60 and 18 * .55 = 9.90

57.60 + 9.90 = 67.50 gallons of antifreeze and we have 90 total gallons

(67.50 / 90) * 100 = 75% correct!

Source: 1728.com/mixture.htm

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4 years ago

A survey about phone service has a margin of error of 5%. Out of 150 people surveyed, 103 said that they were pleased with their

lapo4ka [179]

Answer:

The range of the number of people that are satisfied is option A. 46,968 to 51,912 customers.

Step-by-step explanation:

Hi, to solve this problem you need to calculate the total number of customers that are pleased with the service, based on the 150 people sample.

so:

(72,000 x 103 )÷150 = 49,440

The next step is to calculate the 5% margin of error of that result.

49,440 x 0.05= 2,472

Finally, to obtain the range you need to add and subtract the margin to the total number of customers that are pleased with the service.

49,440-2,472= 46,968

49,440 + 2,472=51,912

So, the range of the number of people that are satisfied is option A. 46,968 to 51,912 customers.

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3 years ago

The population of a country was estimated to be 1.114 x 10^8. On this day, the population of the world was 3.853 x 10^9.

Lelechka [254]

Step-by-step explanation:

To find how many people lived outside of the country we subtract:

3.853 × $10^{9}$ - 1.114 × $10^{8}$ = 3.7146 ×

To find the percentage of people living inside the country, we divide: $\frac{1.114 x10^{8}}{3.853 x10^{9}} =2.8913x10^{-2}$ percent or 2.89%. Which is extremely small.

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3 years ago