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enyata [817]
3 years ago
7

A cyclist must travel 800 km. how many days will the trip take if the cyclist travels 8 h/day at an average speed of 16 km/h?

Mathematics
1 answer:
Mrac [35]3 years ago
7 0
First, you need to find out how much the cyclist will travel a single day. Since the cyclist travels 16 km/h and for 8 h/day, you can easily multiply 16 x 8 = which would be 128 km/day. 

To find how long it will take the cyclist to travel 800km, just divide 800 by the amount they will be going in one day. 800/128= 6.25. That would convert to 6 days and 6 hours. 
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IrinaK [193]

Answer:

1,041.9feet

Step-by-step explanation:

Given the height of the rocket expressed as

y = -16x² + 245x + 104

At maximum height, dy/dx = 0

dy/dx = -32x+245

0 = -32x+245

32x = 245

x = 245/32

x = 7.65625

Get the maximum height

Recall that;

y = -16x² + 245x + 104

Substitute the value of x;

y = -16(7.65625)² + 245(7.65625) + 104

y = -937.890625 + 1,875.78125 + 104

y = 1,041.890625feet

Hcne the maximum height to the nearest foot is 1,041.9feet

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2 years ago
Which equation has only 1 solution? A. c+2=c+2 B. c= -c+2 C. c+2=c-2 D. c-c=2 Please explain.
zhannawk [14.2K]

Answer:

B. c= -c+2

Step-by-step explanation:

A. ...................

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  • c-c= 2-2
  • 0=0

It has infinitely many solutions as the equation is correct for any value of c.

B. ...................

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It has one solution only

C. ...................

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  • 0 = -4

It has no solution as this equation is incorrect

D. ...................

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It has no solution as this equation is incorrect

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3 years ago
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Answer:

D

Step-by-step explanation:

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Answer:

-11/20

Step-by-step explanation:

    2      8   1

 (0-— ÷ (0-—))+—

    3      9   5

           8

Simplify   —

           8/9

2         8     1

 (0 -  — ÷ (0 -  —)) + —

       3         9     5

Simplify   —

           2/3

2   -8     1

 (0 -  — ÷ ——) +  —

       3   9      5

2      -8

Divide  —  by  ——

        3      9

To divide fractions, write the divison as multiplication by the reciprocal of the divisor :

2     -8       2      9

—  ÷  ——   =   —  •  ——

3     9        3     -8

(0--3/4)+1/5

Least Common Multiple:

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Left_M = L.C.M / L_Deno = 5

Right_M = L.C.M / R_Deno = 4

      3 • 5 + 4                 -11

—————————  =  ———

      20                            20

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