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3 years ago

What's the answer? I need help!

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

8 0

Answer:

<h2><u>I can do algebra forever</u></h2>

First we can use distributive property. 2a-10 = 6. So we add 10 on both sides and get 2a=16. Then we divide both sides by 2 so we get a = 8. Therefore proved algebraically that a = 8. I can always do algebra. Feel free to keep asking questions like these. Well feel free to ask any question because this is brainly.

<h2><u>Answer is a = 8, 8 is answer</u></h2><h2><u></u></h2>

<u>brainliest</u>

AlladinOne [14]3 years ago

5 0

Answer:

8 eheh

Step-by-step explanation:

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Please take a look at the picture. Please write your answer with an explanation.

Ahat [919]

Step-by-step explanation:

what answer is needed ? the result of the calculation ?

I assume this is the case.

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and that a combination of - + or + - results in -.

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2 years ago

(-1 + 6) Squared + (4+5) squared

nalin [4]

(-1 + 6)^2 <span>+ (4+5)^2 = </span>106

3 0

3 years ago

Show me how to get the answer to 4.5÷0.25

Lemur [1.5K]

The answer is 18 i think

3 0

3 years ago

Read 2 more answers

You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on con

Assoli18 [71]

Question:

You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on constructing a confidence interval; however, you are not sure how many citizens should be included in the sample. If you want your sample estimate to be within 5 years of the actual mean with a confidence level of 97% , how many citizens should be included in your sample? Assume that the standard deviation of the ages of all the citizens in this community is 18 years.

Answer:

61.03

Step-by-step explanation:

Given:

Standard deviation = 18

Sample estimate = 5

Confidence level = 97%

Required:

Find sample size, n.

First find the Z value. Using zscore table

Z-value at a confidence level of 97% = 2.17

To find the sample size, use the formula below: