Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
The small number is 2 the large number is 11.
4(2)+11(3)=41
2(2)+11=15
11(10) -2(6) = 98
hope that helps
Answer:
The width of the frame must be 12 inches (15in by 12in)
Step-by-step explanation:
Given
See attachment for painting and frame
Required
Determine the dimension of the frame
To do this, we make use of the following scale ratio.
For the painting,
For the frame,
Since she wants to maintain the same ratio; both scale must be the same.
i.e.
Express as fraction
Make w the subject
<em>The width of the frame must be 12 inches i.e. 15in by 12in frame</em>
35.
2*2= 4*2=8
3*3=9*3=27
27+8=35
So the answer is 35. Hope this helps
C is the answer to this question
