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Paraphin [41]
3 years ago
14

Its due today please help

Mathematics
2 answers:
Alborosie3 years ago
8 0

Answer:

5

Step-by-step explanation:

Snezhnost [94]3 years ago
6 0

Answer:

\boxed{0.76} \: is \: correct.

Step-by-step explanation:

let \: the \: unknown \: ounce \: be \to \: u_{kn}\\ if \: 1 \: ounce \: is = 23.8 \: grams \\ then \to \:  u_{kn} =  \frac{18 \:  grams \times 1 \: ounce}{23.8 \: grams } \\ u_{kn} =   \frac{18}{23.8} (1 \: ounce \:) = 0.756302521 \times 1 \: ounce \\  \boxed{u_{kn} =   0.756302521 \: ounce }

♨Rage♨

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pogonyaev

Answer:

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3 0
3 years ago
If the value of x is 3, then what is the value of 2-8x+4x+4
Veronika [31]
Hey there,
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<em>~Top♥</em>
5 0
3 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

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C. x is all real numbers

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