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3 years ago

What type of triangle has 3 sides that are the same length?

2 answers:

wel3 years ago

6 0

The answer is an equilateral triangle.

An equilateral triangle is a triangle in which all 3 side lengths are the same.

Hope this helped☺☺

koban [17]3 years ago

3 0

An equilateral triangle.

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In order to solve the equation −3x + 6 = 5, the first step is to (1 point)

aliya0001 [1]

−3x + 6 = 5 | -6 (first step is: "subtract 6 from both sides" )

-3x = 5-6
-3x = -1 | /(-3) (second step is: "divide by (-3) on both sides" )

 $\displaystyle \\ 
x = \frac{-1}{-3} = \boxed{\frac{1}{3} }$

5 0

3 years ago

Read 2 more answers

If 4x^2 - 100 = 0, the roots of the equation are

ololo11 [35]

$4x^2-100=0 \ \ \ \ \ \ |+100 \\
4x^2=100 \ \ \ \ \ \ \ \ \ \ \ |\div 4 \\
x^2=25 \\
x=\pm \sqrt{25} \\
x=\pm 5 \\
x=-5 \hbox{ or } x=5$

The answer is (3) -5 and 5.

5 0

3 years ago

Marcus earns money from feeding cats and answering emails. He earns $7 a week for each cat he feeds and $0.20 for each email he

Dmitry_Shevchenko [17]

A.
7 times number of cats=pay
if pay=49 then
7 times number of cats=49
divide both sides by 7
number of cats=7

da equaton can be
c=number of cats
7c=49

he fed 7 cats

B.

7c=49
divide both sides by 7
equality property of division
(7c)/7=49/7
math fact
(7/7)c=7
1c=7
identity property of division
c=7
identity property of multiplication
7 cats

C. 7 cats

4 0

3 years ago

I stayed up all night trying to figure out this question but I just can’t

Vilka [71]

Answer:

from what we're given on the drawing, ac and pt are congruent

and from the question format, ab is equal to pq, ac is equal to pr

8 0

3 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago