Answer:
Any of the set of metallic elements occupying a central block (Groups IVB–VIII, IB, and IIB, or 4–12) in the periodic table, e.g., iron, manganese, chromium, and copper. Chemically they show variable valence and a strong tendency to form coordination compounds, and many of their compounds are colored.
Step-by-step explanation:
Answer:(3x+7)(x+2)
Step-by-step explanation:
1) Let's evaluate that expression, given that a=4.9, b=-7, and c=-0.5
Note that we have rewritten it as a fraction so that we can easily operate. Also, we have applied here the PEMDAS order of operations, prioritizing the exponents.
Answer:(-5,-7)
Step-by-step explanation:
Rewrite in Vertex form and use this form to find the vertex (h,k)
9514 1404 393
Answer:
382 square units
Step-by-step explanation:
The central four rectangles down the middle of the net are 9 units wide, and alternate between 8 and 7 units high. Then the area of those four rectangles is ...
9(8+7+8+7) = 270 . . . square units
The rectangles making up the two left and right "wings" of the net are 8 units high and 7 units wide, so have a total area of ...
2×(8)(7) = 112 . . . square units
Then the area of the figure computed from the net is ...
270 +112 = 382 . . . square units
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<em>Additional comment</em>
You can reject the first two answer choices immediately, because they are odd. Each face will have an area that is the product of integers, so will be an integer. There are two faces of each size, so <em>the total area of this figure must be an even number</em>.
You may recognize that the dimensions are 8, 8+1, 8-1. Then the area is roughly that of a cube with dimensions of 8: 6×8² = 384. If you use these values (8, 8+1, 8-1) in the area formula, you find the area is actually 384-2 = 382. That area formula is A = 2(LW +H(L+W)).
