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Art [367]
3 years ago
7

Planes A and B intersect.

Mathematics
2 answers:
olasank [31]3 years ago
5 0

The <em><u>correct answer</u></em> is:

line ED

Explanation:

The intersection of two planes is a line.

Looking at this diagram, line ED is where planes A and B intersect; this means line ED is our answer.

NARA [144]3 years ago
5 0
<span>Planes A and B intersect.

Which describes the intersection of planes A and B?

Line CD

-Line ED

Point C

Point D</span><span>
</span>
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Find each rate in 40 meters in 16 sec
lara31 [8.8K]
<span> Rate = 40/16 = 10/4 = 5/2 = 2.5 meters/second Unit rate = ratio where denominator is 1 = 2.5/1 meters/second </span>
4 0
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Devin has a furniture store. He sold a shoe rack recently for 3450. It cost him just 2300 to make the rack
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Answer:

50%

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2 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
Read 2 more answers
Each side length of a triangle is 4 cm. What type of triangle is it?
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Equilateral, because the sides are equal
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