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3 years ago

A circle has a sector with area 64/5 pi

Mathematics

1 answer:

Helen [10]3 years ago

4 0

Answer:

The area of the circle is $16\pi\ units^2$

Step-by-step explanation:

we know that

The area of complete circle subtends a central angle of 2pi radians

using proportion

Find the area of the circle

$\frac{(64\pi/5)}{(8\pi/5)}= \frac{x}{2\pi}\\\\x=2\pi(64)/8\\\\x=16\pi\ units^2$

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Which is the most accurate way to estimate 25% of 53?

Alex Ar [27]

You can calculate them out and check which one is the most accurate

so if one of the choices was 1/3 of 50, then you would do:
1/3 in the calculator (should be 0.333...) times 50

And you can compare it with the EXACT number, which is:
0.25*53=13.25

This way you can test all the options

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3 years ago

Midpoint (10,4) Endpoint (9,-4), find the coordinates of the other endpoint.

mestny [16]

Answer:

(11, 12)

Step-by-step explanation:

Mid point coordinates:

x = (x₁ + x₂)/2
y = (y₁ + y₂)/2

Since midpoint and one endpoint given (10, 4) and (9, -4), the other endpoint:

x₂ = 2x - x₁ = 2*10 - 9 = 11
y₂ = 2y - y₁ = 2*4 - (-4) = 12

So the other endpoint is: (11, 12)

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3 years ago

The figure is formed from rectangles . Find the total area

Anna35 [415]

It might be c. im not really sure, but that's what I got. sorry if its wrong...

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2 years ago

2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.

kaheart [24]

Answer:

$x=17$

Step-by-step explanation:

$2x+3y=1$

$y=-2-9$

In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, $y$ . In this case, we need to isolate $y$ in the first equation so that both equations $=y$ .

$2x+3y=1$

$3y=-2x+1$

$\frac{3y}{3}=\frac{-2x+1}{3}$

$y=-\frac{2}{3}x+\frac{1}{3}$

With this, we now know that both $-2-9$ and $-\frac{2}{3}x+\frac{1}{3}$ are equal to $y$ , so we can set them equal to each other.

$y=-\frac{2}{3}x+\frac{1}{3}$

$y=-11$

$-\frac{2}{3}x+\frac{1}{3}=-11$

Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for $x$ .

$-\frac{2}{3}x+\frac{1}{3}=-11$

$-\frac{2}{3}x=-11-\frac{1}{3}$

$-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}$

$-\frac{2}{3}x =-\frac{34}{3}$

$-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})$

$x=\frac{102}{6}=17$

$x=17$

Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

4 0

2 years ago

Put the following equation of a line into slope-intercept form, simplifying all

muminat

Answer:

y = 3/4 + 7

Step-by-step explanation:

you must put the equation into the form of y = mx + b

add 6x to both sides and put it in front of the 56

8y = 6x + 56

y must be by itself by x does not so we divide everything by 8

y = 6/8x + 7

we must simplify the fraction 6/8

y = 3/4x + 7

7 0

1 year ago