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astraxan [27]
3 years ago
5

(3.1 x 10^5) (.00000432)​

Mathematics
1 answer:
Ber [7]3 years ago
7 0

Answer:

13.392

Step-by-step explanation:

(3.1×1000000)(.00000432)

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Iodine-125 has a half-life of about 60 days. How many milligrams of a 1000 mg sample will remain after 240 days?
Tomtit [17]

240 days is 4 times the half-life, which means that a sample of 1000 mg will decay to

\dfrac{1000}{2^4}=\dfrac{125}2=62.5\,\mathrm{mg}

after 240 days.

3 0
3 years ago
Use rhombus TQRS below for questions<br> what is the value of x?<br> what is the value of y?
sladkih [1.3K]

The value of x is 1.

The value of y is 4.

Solution:

Given TQRS is a rhombus.

<u>Property of rhombus: </u>

Diagonals bisect each other.

In diagonal TR

⇒ 3x + 2 = y + 1  

⇒ 3x – y = –1 – – – – (1)

In diagonal QS

⇒ x + 3 = y

⇒ x – y = –3 – – – – (2)

Solve (1) and (2) by subtracting

⇒ 3x – y – (x – y) = –1 – (–3)

⇒ 3x – y – x + y = –1 + 3

⇒ 2x = 2

⇒ x = 1

Substitute x = 1 in equation (2), we get

⇒ 1 – y = –3

⇒ –y = –3 – 1

⇒ –y = –4

⇒ y = 4

The value of x is 1.

The value of y is 4.

6 0
4 years ago
What is the solution for 2t &lt;5
Luba_88 [7]
Divide 2 from both sides
t < 5/2
Hope this helps!
6 0
3 years ago
Read 2 more answers
Javier's parents set an amount of money aside when he was born. They earned 4.5% simple interest on that money each year. When J
solmaris [256]

Answer:

Javier's parents set aside $1500 when he was born

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this question, we have that:

E = 1012.50, t = 15, I = 0.045

We have to find P. So

E = P*I*t

1012.50 = P*15*0.045

P = \frac{1012.50}{15*0.045}

P = 1500

Javier's parents set aside $1500 when he was born

6 0
3 years ago
Which best describes the expression b(4-n)
Maru [420]

Answer:

4b-bn

Step-by-step explanation:

3 0
3 years ago
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