Answer:
- the domain is [0,129]
- 112 mm
- 1942
Step-by-step explanation:
1. The function is good for years 1880 to 2009, 0 to 129 years after 1880. Values of x can be anything in the domain [0, 129].
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2. 1950 -1880 = 70. The year 1950 corresponds to x=70, so the function tells us the water level rose ...
f(70) = 1.6·70 = 112 . . . . . mm
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3. We want to find x when f(x) = 100. That will be the solution to ...
100 = 1.6x
100/1.6 = x = 62.5
Then 62.5 years after 1880 is year 1942.5. The water level was 100 mm higher than in 1880 in the year 1942.
N-2,n and n+2;n-3,n and n+3,n-4,n and n+4....
1.q=p-2n
2.q=75000-2*20000
q=75000-40000
q=35000
3.p=90000+2*25000
p=90000+50000
p=140000
Hope this helps :)
A = 1/2 * b * h
b = 14
h = 12
A = 1/2 * 14 * 12
A = 7 * 12 = 84 mm^2
6.34 rounds to 6.
3.95 rounds to 4.
So 6+4=10
