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Veseljchak [2.6K]
3 years ago
13

Kateri draws a square. She wants to draw one line to draw one line to divide the square into 2 triangles. Is it possible for her

to divide the square into 2 obtuse triangles? Explain
Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0
No. Since you can only draw from the corners to get triangles, you will end up with two right triangles because of the corners. If it is a right triangle, it can obviously not be obtuse.
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The diagonals of rectangle nopq intersect at point r. if qr=3x-4 and np=5x+20, solve for x.
FrozenT [24]
2(3x - 4) = 5x + 20
6x - 8 = 5x + 20
subtract 5x from both sides
x - 8 = 20
add 8 to both sides
x = 28


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What is 46,290 in scientific notation?
Snezhnost [94]

Answer:

Step-by-step explanation:

= 4.629 × 10•10•10•10

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5
DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that csc(x)=1/sin(x) and sec(x)=1/cos(x).

Thus:

\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}

=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }

Let's do the first part first: (Recall how to divide fractions)

\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}

For the second term:

\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}

So, all together: (same denominator; combine terms)

\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}

Note the numerator; it can be derived from the Pythagorean Identity:

sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)

Thus, we can substitute the numerator:

\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1

Everything simplifies to 1.

7 0
3 years ago
How are the real solutions of a quadratic equation related to the graph of the quadratic function?
Anika [276]
The solutions you get when you solve the formula are the corresponding y coordinates to your x value. So say a point on your graph is (2,3). The first number is x and the second is y. (x,y). The number you plug into your function is x,or in this case: 2. The solution to the equation when the x value is plugged in is y, or 3. Therefore, giving you a point on your graph.
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Write the point from of the equation for a line that passes through (6,—1) with a slope of 2
Paraphin [41]

Answer:

y = 2x-13

Step-by-step explanation:

The equation for a line is

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Substitute this into y = 2x+b

y = 2x-13

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