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Bas_tet [7]
3 years ago
5

Choose the answer with the correct missing numbers and the correct expression to describe the conversion.

Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

b

brainliest pls

Step-by-step explanation:

Andrews [41]3 years ago
7 0

Answer:

A. 400, 500, 600, M x 100

Step-by-step explanation:

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100 POINTS IF U GET THIS RIGHT!
iVinArrow [24]

Answer:

That is the answer

Hope this helps!

3 0
3 years ago
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A rectangle measures 6 cm by 4 cm. Another rectangle with adjacent sides 8 cm and x cm is geometrically similar to it. Find the
Elis [28]

Answer:

5 1/3 or 5.33333333333333333333333333333333333333333333333333333

Step-by-step explanation:

to find the scale factor, you must divide the two equal sides.

\frac{6}{8}

which equals

\frac{3}{4} or 0.75

Now, the way to get the value of x is to divide 4 by 3/4 0r 0.75

\frac{4}{0.75}

Which equals

5.333 repeating or 5 1/3

Hope this helps. If you have any follow-up questions, feel free to ask.

Have a great day! :)

6 0
3 years ago
Storage tubs were stacked against a wall.The tubs are unit cubes.The tubs are stacked three tubs wide, and two tubs tall
Blizzard [7]

Answer:

6 cubic units

Step-by-step explanation:

step 1

Find the total number of storage tubs

Multiply three tubs wide by two tubs tall

(3)(2)=6\ storage tubs

step 2

Find the total volume of storage

we know that

One storage tub is a unit cube

That means ----> The volume of one storage tub is one cubic unit

Multiply by 6 storage tubs

(1)(6)=6\ units^3

5 0
3 years ago
£8658 is shared equally between 9 people. How much does each person get?<br> £
valkas [14]

Answer:

962

Step-by-step explanation:

8658/9

8 0
2 years ago
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The volume of the cube below is 1/8cm^2 . What is the value of x?
Kipish [7]

We are given

edge of cube =x

we know that formula for volume of cube

V=x^3

we are given

V=\frac{1}{8} cm^3

we can plug value

x^3=\frac{1}{8} cm^3

now, we can solve for x

\sqrt[3]{x^3} =\sqrt[3]{\frac{1}{8} cm^3 }

x=\frac{1}{2} cm............Answer

6 0
3 years ago
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