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3 years ago

PLEASE HELP: Click on the graph to choose the correct answer to the equation.

Mathematics

1 answer:

Reika [66]3 years ago

3 0

Answer:

It's the third one, I hope so. y<1/2x

Step-by-step explanation:

I hope this helps. :)

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$10,000 is invested at two different rates. $2,500 is invested at 4%, and the rest is invested at 5%. How much interest is earne

worty [1.4K]

I'm assuming this is a yearly interest.

2500*.04=100
7500*.05=375

so that would be $475 earned from interest

3 0

3 years ago

∆ XYZ ≅ ∆ MNL<br><br> Find XY

aivan3 [116]

95 because if you do the math you’ll get the answer

4 0

3 years ago

Select all line segment measurements below that could NOT be used to form a triangle. a triangle with the side measurements of 3

lara31 [8.8K]

Answer:

a triangle with the side measurements of 2, 3, and 5 inches

a triangle with the side measurements of 7, 8, and 16 inches

a triangle with the side measurements of 4, 4, and 8 inches

Step-by-step explanation:

A triangle is a polygon shape with three sides and three angles. There are different types of triangles such as isosceles triangle, scalene triangle, equilateral triangle and right angle triangle.

The triangle inequality theorem states that the sum of any two sides of a triangle is always greater than the third side.

For a triangle with the side measurements of 3, 4, and 6 inches:

3 + 4 > 6. This can be a triangle

For a triangle with the side measurements of 2, 3, and 5 inches:

2 + 3 is not greater than 5, hence it cannot be a triangle

For a triangle with the side measurements of 3, 3, and 4 inches:

3 + 3 > 4. This can be a triangle

For a triangle with the side measurements of 5, 5, and 5 inches

5 + 5 > 5. This can be a triangle

For a triangle with the side measurements of 4, 4, and 8 inches:

4 + 4 is not greater than 8, hence it cannot be a triangle

For a triangle with the side measurements of 7, 8, and 16 inches:

7 + 8 is not greater than 16, hence it cannot be a triangle

8 0

3 years ago

An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp

mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0

2 years ago

Proper order from least to greatest 2/3,7/6,1/8,9/10

notsponge [240]

It's already in order

5 0

3 years ago