Answer:
9/16
Explanation:
The cross was Aa Bb CC X Aa Bb cc
Because genes assort independently, we can analyze each of them separately in the cross, calculate the probability of getting offpsring with a dominant allele, and then multiply each of those probabilities to obtain the overall probability of having A_B_C_ progeny.
<u>A/a</u>
Aa x Aa ---> 3/4 A_, 1/4 aa
<u>B/b</u>
Bb x Bb ---> 3/4 B_, 1/4 bb
<u>C/c</u>
CC x cc ---> 1 C_
3/4 × 3/4 × 1 = 9/16 A_B_C_ offspring.
A stopwatch would provide the most accurate measurement when sprinting
B. Gametophytes produce diploid gamers (the gametes are haploid)
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