L = 1 in
w = 5 in
h = 3 in
d = 5.9160797830996 in
S = 46 in2
V = 15 in<span>3
i don't know which one your looking for so i solved for all the measure hope i hepled
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Answer:
[4, -1]
Step-by-step explanation:
Using the Elimination Method:
3x + y = 11
5x - y = 21
__________
8x = 32
__ ___
8 8
x = 4 [Plug this back into both equations to get the y-coordinate of -1]; -1 = y
The <em>y</em>'s are already <em>additive</em><em> </em><em>inverses</em><em> </em>[result in 0], canceling each other out.
I am joyous to assist you anytime.
Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
If so then it is not rational Square root of 2 is irrational and any number formed by multiplying or dividing it by a rational number is also irrational.
Answer:
x=+5
Step-by-step explanation:
3(x+2)-2x-7=-(-5x-1)-2(x+6)
We move all terms to the left:
3(x+2)-2x-7-(-(-5x-1)-2(x+6))=0
We add all the numbers together, and all the variables
-2x+3(x+2)-(-(-5x-1)-2(x+6))-7=0
We multiply parentheses
-2x+3x-(-(-5x-1)-2(x+6))+6-7=0
We calculate terms in parentheses: -(-(-5x-1)-2(x+6)), so:
-(-5x-1)-2(x+6)
We multiply parentheses
-(-5x-1)-2x-12
We get rid of parentheses
5x-2x+1-12
We add all the numbers together, and all the variables
3x-11
Back to the equation:
-(3x-11)
We add all the numbers together, and all the variables
x-(3x-11)-1=0
We get rid of parentheses
x-3x+11-1=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5