David played a slot machine. W(t) models his winnings (in dollars, where a negative number means David is losing) as a function
of time t (in hours).
When did David's winnings decrease faster?
A. Between 1 and 4.5 hours since he started playing
B. Between 4.5 and 6 hours since he started playing
C. The winnings decreased at the same rate over both intervals
When did David's winnings decrease faster?
A. Between 1 and 4.5 hours since he started playing
B. Between 4.5 and 6 hours since he started playing
C. The winnings decreased at the same rate over both intervals
1 answer:
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The water level increases by 0.608 meters per minute when the water is 3.5 m deep
<h3>How to determine the rate?</h3>The given parameters are:
- Radius, r = 3
- Height, h = 7
- Rate in, V' = 4.3m^3/min
The relationship between the radius and height is:
r/h = 3/7
Make r the subject
r = 3h/7
The volume of a cone is;
This gives
Expand
Differentiate
Make h' the subject
When the water level is 3.5.
We have:
Also, we have:
V' = 4.3
So, the equation becomes
Evaluate the products
Evaluate the quotient
h' = 0.608
Hence, the water level increases by 0.608 meters per minute
Read more about volumes at:
#SPJ1
Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.
[23] ABD = 42°, DBC = 35°
(4x - 2) + (3x + 2) = 77°
4x+ 3x + 2 - 2 = 77°
4x+ 3x= 77°
7x= 77°
x= 11°
-
ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°
DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°
[24] ABD = 62°, DBC = 78°
(4x - 8) + (4x + 8) = 140°
4x + 4x + 8 - 8 = 140°
4x + 4x = 140°
8x = 140°
8x = 140°
x = 17.5°
-
ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°
DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°
