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just olya [345]
4 years ago
7

David played a slot machine. W(t) models his winnings (in dollars, where a negative number means David is losing) as a function

of time t (in hours).
When did David's winnings decrease faster?
A. Between 1 and 4.5 hours since he started playing
B. Between 4.5 and 6 hours since he started playing
C. The winnings decreased at the same rate over both intervals

Mathematics
1 answer:
tester [92]4 years ago
3 0

Answer:

The answer is B. Between 4.5 and 6 hours since he started playing

Step-by-step explanation:

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Question 2 (1 point)
Kisachek [45]

Answer:

2. c/8

3. b/15

4. b/25

Those are the only i know-

Step-by-step explanation:

8 0
3 years ago
X^2-8x-36=0<br> solve by completing the square <br> ANSWER ASAP
larisa86 [58]

Answer:

hope it helps

7 0
3 years ago
The ordered pairs in the table below represent a linear function.
Lilit [14]

Answer:

The slope is 2

Step-by-step explanation:

Given

x   y

2    3

5    9

Required

Determine the slope

First, we have:

(x_1,y_1) = (2,3)

(x_2,y_2) = (5,9)

The slope is then calculated as:

m = \frac{y_2 - y_1}{x_2 - x_1}

This gives:

m = \frac{9-3}{5-2}

m = \frac{6}{3}

m =2

<em>Hence, the slope is 2.</em>

5 0
3 years ago
Read 2 more answers
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=20$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0
3 years ago
Which of the following ordered pairs make this equation true? Y = 2x - 7 A. (1,9) B. (-3, 4) C. (4,1) D. (-1, 5)​
gregori [183]

Answer:

(4,1)

Step-by-step explanation:

Using substitution you can determine that 2*4-7 is in fact equal to 1

3 0
3 years ago
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