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3 years ago

The probability that a person in the United States has type B+ blood is 13%.

Mathematics

1 answer:

blondinia [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Given that the probability that a person in the United States has type B+ blood is 13%.

Since four unrelated people in the United States are selected at random, we can say that each person is independent of the other to have B+ blood group.

Let X be the number of persons who have blood group B+ in the group of 4 persons.

X is Binomial with p = 0.13

a) P(X = 4) = $(0.13)^4 = 0.000286$

b) P(x =0) = $(1-0.13)^4 = 0.572898$

c) $P(X\geq 10 = 1-P(0) = 0.427102$

d) All having B+ is unusual since probability is very negligible

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BRAINZLIEST

nikdorinn [45]

Answer:

liam

Step-by-step explanation:

We have, 25% × x = 150

or,

100

× x = 150

Multiplying both sides by 100 and dividing both sides by 25,

we have x = 150 ×

100

x = 600

If you are using a calculator, simply enter 150×100÷25, which will give you the answer.

4 0

3 years ago

Read 2 more answers

The coordinates of the vertices of quadrilateral DEFG are D(−2, 5) , E(2, 4) , F(0, 0) , and G(−4, 1) .

daser333 [38]

Answer: The correct option is a.Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length.

Explanation:

It is given that coordinates of the vertices of quadrilateral DEFG are D(−2, 5) , E(2, 4) , F(0, 0) , and G(−4, 1) .

The distance formula for two points is given below,

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$DE=\sqrt{(2+2)^2+(4-5)^2}=\sqrt{17}$

$EF=\sqrt{(0-2)^2+(0-4)^2}=\sqrt{20}$

$FG=\sqrt{(-4-0)^2+(1-0)^2}=\sqrt{17}$

$DG=\sqrt{(-4+2)^2+(1-5)^2}=\sqrt{20}$

Slope formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Slope of DE,

$m_1=\frac{4-5}{2+2}= \frac{-1}{4}$

Slope of EF,

$m_2=\frac{0-4}{0-2}= 2$

Slope of FG,

$m_3=\frac{1-0}{-4-0}= \frac{-1}{4}$

Slope of DG,

$m_4=\frac{1-5}{-4+2}= 2$

The slope of opposite sides are equal, it means the opposite sides are parallel.

All four sides do not have the same length. It means it is not a rhombus.

From the figure it is noticed that the opposite sides are parallel.

Therefore, the correct option is a.Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length.

3 0

4 years ago

Read 2 more answers

What’s the equation for the order pairs (1,-5) and (-2,5)

liq [111]

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})\qquad
(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-5)}{-2-1}\implies \cfrac{5+5}{-2-1}\implies \cfrac{10}{-3}$

$\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-(-5)=-\cfrac{10}{3}(x-1)\implies y+5=-\cfrac{10}{3}x+\cfrac{10}{3}
\\\\\\
y=-\cfrac{10}{3}x+\cfrac{10}{3}-5\implies y=-\cfrac{10}{3}x-\cfrac{5}{3}$