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3 years ago

Match the numbers with the correct label

Mathematics

1 answer:

hodyreva [135]3 years ago

7 0

Answer:

ima let u answer some of it

Step-by-step explanation:

first find common denominators

then compare and place

You might be interested in

#1. The area of a square tile is 53.4cm^2. find the length of one side of the tile, rounded to the nearest 10th.

andrey2020 [161]

Problem 1

<h3>Answer: 7.3</h3>

Explanation: Apply the square root to the area to get the side length. This only applies to areas that are squares (hence the name).

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Problem 2

<h3>Answer: C) 1.3</h3>

Explanation: Use your calculator to find that choices A,B,D plugged into the square root function yield terminating decimal values. "Terminating" means "stop". This implies that they are perfect squares (though not perfect squares in the sense of whole number perfect squares which you may be used to). Choice C is the only value that has a square root that leads to a non-terminating decimal. The digits of this decimal go on forever without any pattern. The value is irrational.

sqrt(5.29) = 2.3 terminating decimal
sqrt(13.69) = 3.7 terminating decimal
sqrt(1.3) = 1.140175425 keeps going forever without any pattern
sqrt(0.09) = 0.3 terminating decimal

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Problem 3

<h3>Answer: 23.6 feet approximately</h3>

Explanation: Apply the square root to 15.5 to get roughly 3.937; this is the approximate side length of one square. Six of these tiles placed together will lead to a total length of roughly 6*3.937 = 23.622 which rounds to 23.6 feet. Like with problem 1, the square root being used like this only works for square areas.

5 0

4 years ago

Read 2 more answers

One hat and Two shirts costs $21. Two hats and one shirt $18. Megan has exactly enough money to buy one hat and one shirt. How m

xxTIMURxx [149]

Suppose Megan has enough money to buy 1 hat and 2 shirts for $21 and then another 2 hats and 1 shirt for $18. In total, she has bought 3 hats and 3 shirts for $39. But she has enough for only 1 hat and 1 shirt and so Megan has 39 ÷ 3 = $13.

8 0

3 years ago

A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce

brilliants [131]

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = $\frac{14000}{30} = \frac{1400}{3}$ lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = $\frac{1400}{3} \times 16=\frac{22400}{3}$ oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = $\frac{22400}{3} \div 3.4 = 2196$ fish

Thus, the killer whale needs to eat 2196 fish.

8 0

4 years ago

Find the slope of the line

Maslowich

Answer:

1/2

Step-by-step explanation:

(2,1)(4,2)

x1-y1/x2-y2

slope:m=1/2

7 0

3 years ago

A dietitian wants to know the average time spent on breakfast in a primary school. The dietitian randomly samples 25 students an

blsea [12.9K]

Answer:

The right options are:

a. The margin of error is 0.632

f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>Select one or more:</em>

<em>a. The margin of error is 0.632</em>

<em>b. The margin of error is 1264.</em>

<em>C. The margin of error is 0.600.</em>

<em>d. We believe that the true mean time spent on breakfast is between 11.968 and 13.232 minutes.</em>

<em>e. If we take many other samples from this population, 95% of them will have a sample mean that is between 11968 and 13232.</em>

<em>f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.</em>

The margin of error can be calculated from the bounds of the confidence interval as:

$E=\dfrac{UL-LL}{2}=\dfrac{13.232-11.968}{2}=\dfrac{1.264}{2}=0.632$

As the confidence interval is calculated at 95% confidence, we are 95% confident that the true mean is within the calculated interval. We are not 100% confident although (that's why Option d is false).

This interval does not give us information about the sampling distribution (option e is false).

8 0

3 years ago