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Novosadov [1.4K]
3 years ago
15

If a marble is randomly chosen from a bag that contains exactly 8 red marbles, 6 blue marbles, and 6 white marbles. What is the

probability that the first marble will NOT be white and the second will BE white?​
Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

Step-by-step explanation:

so theres 8 red marbles, 6 blue marbles, and 6 white marbles so that makes

8 + 6 + 6 = 20 marbles in total

the probability of the marble being white is 6/20 or 3/10

so the probabilty of the marble NOT being white is 1 - (3/10) = 7/10

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If you're trying to make an inequality, it would be:

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A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
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Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

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