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ANTONII [103]
3 years ago
15

Question 1

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

A). Surface area = 222 cm²

Volume = 180 cm³

B). Surface area = 375 cm²

Volume = 360 cm³

C). % increase in surface area = 67.57%

% increase in volume = 100%

Step-by-step explanation:

In the figure attached base of a prism has been given.

A). Surface area of the prism = (Perimeter of the base of the prism) × height + 2(area of the base)

Perimeter of the base = 5 + 3 + 2 + 2 + 2 + 3 + 5 + 8

                                       = 30

Area of the base = 8×5 - 2×2 = 36 cm²

Surface area of the prism = 30×5 + 2×(36)= 222 cm²

Volume of the prism = volume of the bigger prism - volume of the smaller prism cut off

                                  = 8×5×5 - 2×2×5

                                  = 200 - 20

                                  = 180 cm³

B). Surface area of the prism if it's height is 10 cm,

Surface area = 30×10 + 2×(36) = 372 cm²

Volume of the prism = 8×5×10 - 2×2×10

                                   = 400 - 40

                                   = 360 cm³                                      

C). Increase in surface area = 372 - 222 = 150 cm²

% increase in the surface area = \frac{150}{222}\times 100 = 67.57%

Increase in volume = 360 - 180 = 180 cm³

% increase in volume = \frac{180}{180}\times 100 = 100%

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almond37 [142]

Answer:

The minimum surface area of the container is 276.791 square units.

Step-by-step explanation:

Let be A(r) = \pi\cdot r^{2} + \frac{1000}{r}, \forall \,r \in \mathbb{R}, r \geq 0. The first and second derivatives of such function are, respectively:

First derivative

A'(r) = 2\cdot \pi \cdot r -\frac{1000}{r^{2}}

Second derivative

A''(r) = 2\cdot \pi +\frac{2000}{r^{3}}

The critical values of r are determined by equalizing first derivative to zero and solving it: (First Derivative Test)

2\cdot \pi \cdot r -\frac{1000}{r^{2}} = 0

2\cdot \pi \cdot  r^{3} - 1000 = 0

r = \sqrt[3]{\frac{1000}{2\pi} }

r \approx 5.419 (since radius is a positive variable)

To determine if critical value leads to an absolute minimum, this input must be checked in the second derivative expression: (r \approx 5.419)

A''(5.419) = 2 + \frac{2000}{5.419^{3}}

A''(5.419) = 14.568

The critical value leads to an absolute minimum, since value of the second derivative is positive.

Finally, the minimum surface area of the container is:

A(5.419) = \pi\cdot (5.419)^{2} + \frac{1000}{5.419}

A(5.419) \approx 276.791

The minimum surface area of the container is 276.791 square units.

7 0
3 years ago
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