Question

Please help me!!! U will be named the brainliest.

Answer 1

Answer:

perimeter = 44.05 yd

area = 164.25 yd^2

Step-by-step explanation:

The figure is shaped like a trapezoid with a semicircle.

Perimeter:

We add the lengths of the three sides of the trapezoid and the circumference of the semicircle.

perimeter = 15 + 11.2 + 10 + 0.5 * 3.14 * 5

perimeter = 44.05 yd

Area:

We find the area of the trapezoid and add to it the area of the half circle.

area = 0.5(10)(10 + 15) + 0.5(3.14)(5^2)

area = 164.25 yd^2

Answer 2

19a. Well, we can start off by finding the perimeter of the quadrilateral and then move on to the semi-circle. We know that the radius of the semi-circle is 5, right? Therefore, we can also say that the diameter is 10, since 5*2 is 10.

Sides of the quadrilateral: 11.2, 10, 15, 10

Add them all up:

11.2+10+15+10 = 46.2

Now for the semicircle.

The perimeter of a normal is 2πr right? Essentially, we just need to change that formula up a bit so it looks like this:

πr + d

It may seem a bit confusing, but you can't just divide the normal equation by 2. You have to "walk" across the semi-circle, too! This means that we also have to add the diameter. (We already know it's 10, because of the first question)

So, input all the terms:

π(5) + 10 = 25.7079 (I don't know how specific it has to be)

Add the perimeter of the quad and the semi-circle:

25.7079+46.2 = 71.9079 yards

19b. First, let's find the area of the quad.

The quadrilateral is essentially a triangle and a square shoved togther, so let's split the quadrilateral up and combine the areas later.

15-10 = 5, right? This means that the height of the triangle will be 5, and the width will be 10 (diameter of the circle!)

1/2*5*10 = 25 yd^2

Now for the square:

The width and the length are both ten. 10*10 = 100 yd^2

100 + 25 = 125 yd^2

Now for the semi-circle (Almost done!)

The formula for the area of a circle is πr^2, so we just have to divide it by 2 (no need to add the diameter, we don't have to "walk" along it)

The new formula we get it πr^2/2

Input values:

π*5^2/2 = 25π/2 = 39.2699

Add all the values:

125 + 39.2699 = 164.2699 yds^2

TLDR;

Perimeter = 71.9079 yards

Area = 164.2699 yds^2

Good luck!!