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-Dominant- [34]
3 years ago
10

Sarah has gone to work for 60 days. On 39 of those days, she arrived at work before 8:30 A.M. On the rest of the days she arrive

d after 8:30A.M. What is the experimental probability she will arrive after 8:30 A.M. on the next day she goes to work?
Mathematics
1 answer:
IgorC [24]3 years ago
4 0
There is a 35%  chance she will arrive after 8:30AM
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Answer:

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Step-by-step explanation:

5C5

= 5! / (5! (5 - 5)!)

= 5! / 5! 0!       (0! =1)

= 1/1

= 1

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What's 20% of £158.08
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20% * 158.08 =31.616
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Tom worked at Home Depot over the summer and saved $2,000. He invested his earnings in an account that paid 4.5% interest compou
yuradex [85]

I believe the result would be about $2,282.80 dollars. It might have some extra cents added to it but this is about the correct answer.

2000 * 0.045 = 90 + 2000 = 2090

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2282.80 is the answer.

Hope this Helps!!

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3 0
3 years ago
Edward walked 3/4mile from his home to the park. Then he walked 2/4 mile from the park to the library.which distance is shorter?
ANEK [815]
The distance from the park to the library 2/4<3/4
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4 years ago
What is the length of the segment, endpoints of which are intersections of parabolas y=x^2− 11/4 x− 7/4 and y=− 7/8 x^2+x+ 31/8
kobusy [5.1K]

Answer:

The length of line segment is 5

Step-by-step explanation:

we are given equation of parabolas as

y=x^2-\frac{11}{4}x-\frac{7}{4}

y=-\frac{7}{8}x^2+x+\frac{31}{8}

Firstly, we will find intersection points

we can set them equal

and then we can solve for x

x^2-\frac{11}{4}x-\frac{7}{4}=-\frac{7}{8}x^2+x+\frac{31}{8}

Multiply all sides by 8

x^2\cdot \:8-\frac{11}{4}x\cdot \:8-\frac{7}{4}\cdot \:8=-\frac{7}{8}x^2\cdot \:8+x\cdot \:8+\frac{31}{8}\cdot \:8

8x^2-22x-14=-7x^2+8x+31

15x^2-30x-45=0

now, we can factor it

15(x^2-2x-3)=0

15(x-3)(x+1)=0

x=-1,x=3

now, we can find y-values

At x=-1:

y=(-1)^2-\frac{11}{4}(-1)-\frac{7}{4}

y=2

so, we get point as

(-1,2)

At x=3:

y=(3)^2-\frac{11}{4}(3)-\frac{7}{4}

y=-1

so, we get point as

(3,-1)

now, we can find distance between these two points

(-1,2)

x1=-1 , y1=2

(3,-1)

x2=3 , y2=-1

now, we can find distance

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

now, we can plug values

D=\sqrt{(3+1)^2+(-1-2)^2}

D=5

So,

The length of line segment is 5

6 0
3 years ago
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