From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
The answer would be D) x = 11.
Add 5 to both sides (5x = 50 + 5)
Simplify 50 + 5 to 55 (5x = 55)
Divide both sides by 5 (x = 55/5)
Simplify 55/5 to 11 (x = 11)
Answer:
Option (1)
Step-by-step explanation:
By the property of alternate segment theorem,
"Angle formed between the tangent and the chord in a circle measures the half of the measure of the intercepted arc"
m(∠EFG) =
× m(minor arc FG)
minor arc FG = 2m(∠EFG)
= 2(76°)
= 152°
Therefore, Option (1) will be the correct option.
Answer:
y = x + -2.3
x = -y - 2.3 (but why would one need this?...)
Step-by-step explanation:
(6.1 - (-9.7))/(8.4 - (-7.4)) = 15.8/15.8 = 1
6.1 = 8.4 + b
b = -2.3
Answer:
e^-1.6094 = 0.2
Step-by-step explanation:
The inverse of In is e
If In 0.2 = -1.6094
Then e^-1.6094 = 0.2