If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Take second equation here,
2x + 9 = -12
2x = -12 - 9
2x = -21
Multiply by 2,
4x = -42
Now, substitute the vaue of 4x in 1st equation,
-42 - y = 2
-y = 2 + 42
y = -44
In short, Your Answer would be -44
Hope this helps!
No because a square pyramid must hav a square for its base and a square is not a triangle
answer is not possible
Answer:
See Explanation Below
Step-by-step explanation:
Your question isn't clear; However, I'll solve in two ways
1. Diameter = 14 cm
2. Radius = 14 cm
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<em>When Diameter = 14 cm</em>
Given


Required
Calculate the area of the circle
First, the radius has to be solved;



Using the given formula;
The area is as follows




<em>When Radius = 14 cm</em>
Given


Required
Calculate the area of the circle
Using the given formula;
The area is as follows




The expression for five groups of a number added to seventeen.
Let the number be X
Five groups of the number will be 5X
The required expression will be
5(X) +17