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svetlana [45]
3 years ago
14

PRECALCULUS HONORS HELP ME PLZ AND THANKS

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Inequalities are used to show the relationship between unequal expressions

  • <em>The set notation of (5) and (6) are: </em>\{x : -6 > x \ge -2\}<em> and </em>\{x:-4 < x \ge 6\}<em>.</em>
  • <em>See attachmen</em>t for the graphs

The following should be notated when plotting the graph of an inequality

  • < and > are represented with open circles, while \leq and \geq are represented with closed circles
  • The arrows of and \le point to the left, while the arrows of > and \geq point to the right.

So, we have:

(a)\ -8 < x

Rewrite as:

x > -8

The graph of x > -8 will point to the right, and it will use an open circle

(b)\ -6 > x \ge -2

Split the inequality:

-6 > x and x \ge -2

<em>It is not possible for -6 to be less than x and at the same time, x is greater than or equal to -2.</em>

<em />

Hence. -6 > x \ge -2 cannot be represented on a graph

(c)\ -4

Split the inequality:

-4 < x and x \ge 6

-4 < x means that -4 is less than x or x is greater than -4.

So, we have:

x > -4 and x \ge 6

If x > -4 and x \ge 6, then we make use of x > -4 because it contains more values of x.

The graph of x > -4 will point to the right, and it will use an open circle

Read more about inequalities at:

brainly.com/question/11612965

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Read 2 more answers
2. You are given the hyperbolic relation modeled by xy = -2. Do the following: a) Rewrite the relation such that the dependent v
N76 [4]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given equation is :

  • xy =  - 2

1. The relationship such that dependent variable (y) is isolated is :

  • y =   \dfrac{ - 2}{x}

2. The table accompanying this equation :

  • x = -4 and y = 0.5

  • x = -1 and y = 2

  • x = - 0.5 and y = 4

  • x = 0 and y = undefined

  • x = 0.5 and y = -4

  • x = 1 and y = -2

  • x = 4 and y = -0.5

3. graph of the given equation is in attachment ~

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