<h3>
Answer: 37</h3>
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Work Shown:
We have a triangle with sides a,b,c such that
The third side c can be represented by this inequality
b-a < c < b+a
which is a modified form of the triangle inequality theorem.
Plug in the given values to get
b-a < c < b+a
20-17 < c < 20+17
3 < c < 37
The third side length is between 3 and 37; it cannot equal 3, and it cannot equal 37. So we exclude both endpoints.
Of the answer choices, the values {7,20, 12} are in the range 3 < c < 37.
The value c = 37 is not in the range 3 < c < 37 because we can't have the third side equal to either endpoint. Otherwise, we get a straight line instead of a triangle forming.
So that's why 37 is the only possible answer here.
Consecutive integers are 1 apart
so the 4 are
x, x+1,x+2,x+3
they add to 8
x+x+1+x+2+x+3=8
4x+6=8
minus 6 both sides
4x=2
divide both sides by 4
x=1/2
false, 1/2 is not an integer
if it was adding to 18, then the integers would be 3,4,5,6
but we can't find consecutive integers that add to 8
Find the common ratio. (The number you multiply or divide.) 3. Create a recursive formula<span> by stating the first term, and then stating the </span>formula<span> to be the common ratio times the previous term.</span>
Answer:
Step-by-step explanation:
Solve for x=0 and x=1
y(0)=2(3^0)=2(1)=2 so (0,2) is a point.
y(1)=2(3^1)=2(3)=6 so (1,6) is a point.
Only graph B has those two points.
