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Setler79 [48]
3 years ago
9

You have a normal model. The population mean is 500 and standard deviation is 100. Which of the following options would be the c

orrect way to represent the information?a. N(500, 100)b. z(500, 100)c. N(100, 5)d. N(100, 500)
Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

a. N(500, 100)

Step-by-step explanation:

The normal probability distribution, with mean M and standard deviation S, can be represented in the following notation.

N(M,S).

In this problem, we have that:

Mean = 500

Standard deviation = 100

Which of the following options would be the correct way to represent the information?

a. N(500, 100)

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Read 2 more answers
Michmoo Computer Company sells computers and computer parts by mail. The company assures its customers that products are mailed
Anastaziya [24]

Answer: (60.858, 69.142)

Step-by-step explanation:

The formula to find the confidence interval for mean :

\overline{x}\pm z_c\dfrac{\sigma}{\sqrt{n}} , where \overline{x} is the sample mean , \sigma is the population standard deviation , n is the sample size and z_c is the two-tailed test value for z.

Let x represents the time taken to mail products for all orders received at the office of this company.

As per given , we have

Confidence level : 95%

n= 62

sample mean : \overline{x}=65 hours

Population standard deviation : \sigma=18 hours

z-value for 93% confidence interval: z_c=1.8119  [using z-value table]

Now, 93% confidence the mean time taken to mail products for all orders received at the office of this company :-

65\pm (1.8119)\dfrac{18}{\sqrt{62}}\\\\ 65\pm4.142\\\\=(65-4.142,\ 65+4.142)\\\\= (60.858,\ 69.142)

Thus , 93% confidence the mean time taken to mail products for all orders received at the office of this company : (60.858, 69.142)

8 0
3 years ago
What is bigger 3/7 or 2/10?
yanalaym [24]
3/7. if you make them equivalent fractions it would be 30/70 or 14/70. 30/70 is bigger.
7 0
3 years ago
Question 13
charle [14.2K]

The amount to be invested today so as to have $12,500 in 12 years is  $6,480.37.

The amount that would be in my account in 13 years is $44,707.37.

The amount I need to deposit now is $546.64.

<h3>How much should be invested today?</h3>

The amount to be invested today = future value / (1 + r)^nm

Where:

  • r = interest rate = 5.5 / 365 = 0.015%
  • m = number of compounding = 365
  • n = number of years  = 12

12500 / (1.00015)^(12 x 365) = $6,480.37

<h3>What is the future value of the account at the end of 13 years?</h3>

Future value = monthly deposits x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

  • r = interest rate = 5.3 / 12 = 0.44%
  • n = 13 x 12 = 156

200 x [{(1.0044^156) - 1} / 0.0044] = $44,707.37

<h3>What should be the monthly deposit?</h3>

Monthly deposit = future value / annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

  • r = 6.7 / 12 = 0.56%
  • n = 2 x 12 = 24

$14,000 / [{(1.0056^24) - 1} / 0.0056] = $546.64

To learn more about annuities, please check: brainly.com/question/24108530

#SPJ1

4 0
2 years ago
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