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inna [77]
3 years ago
15

PLEASE HELP

Mathematics
1 answer:
grin007 [14]3 years ago
6 0
The answer should be 8 feet
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Suppose that x and y vary inversely and that y = 5 when x = 1. What is y when x = 15?
LiRa [457]

Answer:

Y=1/3

Step-by-step explanation:

X=k/y

So let's make k the subject of formula

k=xy

x=1,y=5

So let's substitute

k=1×5

k=5

So we are to determine the value for y when x is 15

So let's solve

Y=k/x

Y=5/15

Y=1/3

Y=0.333333~0.3

7 0
3 years ago
dollars of a Class party is 59 + 13 in where in is the number of people attending what is the cost for 44 people
Alina [70]
Plug in 44
so
59+13(44) = 631
7 0
3 years ago
What is -3/4 x 7/8 <br> whats negative three over four times seven over eight.
UNO [17]

Answer:

-21/32

Step-by-step explanation:

It's easier to do this multiplication mentally if we rewrite the expression as follows:

 -3        7       -21

------ * ------ = ---------

  4         8       32

5 0
2 years ago
Find the equation of the following line:
elena-s [515]

Answer:

I don't really understand this question

Step-by-step explanation:

I don't really understand this question

3 0
2 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
2 years ago
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