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3 years ago

45% of 40 is 18% of what number?

Mathematics

2 answers:

kotykmax [81]3 years ago

7 0

Answer: 100
Explain:
45% of 40 is 18 (0.45x40=18)
18% of 100 is 18 (18/100=0.18x100=18)

I hope it makes sense

aev [14]3 years ago

4 0

Answer:

Step-by-step explanation:

40 is 18% of 45

The number that equals 18 is 45.

Answer: 45

<em><u>Hope this helps. </u></em>

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Find the degree of the monomial.<br>3b2c

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Step-by-step explanation:

The degree of the given monomial = 2 + 1 = 3

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Factor completely 3x2 − 11x 8. (x 4)(3x − 2) (x − 2)(3x − 4) (x 1)(3x − 8) (x − 1)(3x − 8).

earnstyle [38]

The factors of the equation $3x^{2} -11x+8$ will be $(3x-8)(x-1)$

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When we split the equation into two groups we will get

$3x^{2} -3x-8x+8$

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Now taking (x-1) common

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Convert the expression (√5)(∛5) to exponential form. Show your work

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3 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
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Another way is apply the formula A=1/2*base*altitude,
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3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

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