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2 years ago

Help me plsss....

Mathematics

2 answers:

eimsori [14]2 years ago

6 0

Answer:

If it took the motorcycle 2 hours to cover 20km, then the average speed is 10km per hour.

Speed is equal to distance over time. So 20km divided by 2 hours is 10 km per hour.

DIA [1.3K]2 years ago

4 0

Step-by-step explanation:

i hope this is gonna help......

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X + 5y = 28 2x + 3y = 21 Solve for x and y.

snow_tiger [21]

First what we gonna do is solve for y.
x+5y=28 Subtract 5y both sides.
-5y -5y
x=-5y+28 Then you have to replace x with the equation.
2(-5y+28)+3y=21 Multiply.
-10y+56+3y=21 Combine like terms and subtract 56 both sides.
-56 -56
-7y=-35 Divide -7 both sides.
y=5 Simplify.
x=-5(5)+28 Multiply and add.
x=-25+28
x=3
Heres your answer x=3 and y=5.

6 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

Put the equation: 2x+3y=9 into slope-intercept form

Katarina [22]

Answer:

2x − 3y = 9 2 x - 3 y = 9 The slope-intercept form is y = mx+ b y = m x + b, where m m is the slope and b b is the y-intercept. y = mx +b y = m x + b Rewrite in slope-intercept form.

Step-by-step explanation:

answer is y = 2/3x-3

4 0

3 years ago

I need help on my corrections! Can someone help me please if u do know!!

Harlamova29_29 [7]

Looks good for high school math make sure the teacher sees you're work clearly and know what the numbers are overall you should be good

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2 years ago

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Mumz [18]

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3 years ago