First distribute the 2, then add 7 to that side, so you have 2g+17=-4g+g , subtract 2g and it should be easy to find from there lol
The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is

a1=1
r=2
we want to find

(since we minus 1, the highest exponet is 9 so add 1 to make it correct)



Answer:
and 
Step-by-step explanation:
Assume that the terminal side of thetaθ passes through the point (−12,5).
In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.
Using Pythagoras theorem:




Taking square root on both sides.

In a right angled triangle




In second quadrant only sine and cosecant are positive.
and 
2arctan(2/5) = 44°
180° -44° = 136°
The angles are 44°, 136°.