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serg [7]
3 years ago
11

The estimated probability of a football player scoring a touchdown during a particular game is 26%. If several simulations of th

e football player playing two games were performed, in what percentage of the simulations would the football player be most likely to get a touchdown in each of the two games?
A. 26%
B. 15%
C. 52%
D. 7%
Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

The correct option is D.

Step-by-step explanation:

It is given that the estimated probability of a football player scoring a touchdown during a particular game is 26%.

The probability of a football player scoring a touchdown during a particular game is \frac{26}{100}.

We have to find the percentage of the simulations would the football player be most likely to get a touchdown in each of the two games.

The probability of a football player scoring a touchdown during two games is

P=\frac{26}{100}\times \frac{26}{100}

P=0.0676

Multiply the probability by 100 to find the percentage of the simulations would the football player be most likely to get a touchdown in each of the two games.

P=0.0676\times 100=6.76\approx 7\%

Therefore the correct option is D.

Goryan [66]3 years ago
3 0
I believe the answer is C
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4 0
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This is uhh due by 8 tommorow mornin please help me
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6 0
3 years ago
What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
mars1129 [50]
The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
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the sum of a geometric seequence is
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we want to find S_{10} (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

S_{10}=\frac{1(1-2^{10})}{1-2}
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3 0
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zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

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Taking square root on both sides.

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In a right angled triangle

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\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
The lengths of the diagonals of a rhombus are 2 inches and 5 inches. Find the measures of the angles of the rhombus to the neare
Radda [10]
2arctan(2/5) = 44°
180° -44° = 136°

The angles are 44°, 136°.
4 0
3 years ago
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