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3 years ago

A volleyball court has an area of 1,800 square feet. The length of the court is 60 feet. What is the width of the court?

Mathematics

1 answer:

julsineya [31]3 years ago

8 0

Answer: 30 ft

Step-by-step explanation:

Area = l x w

1800 = 60 x w

W = 1800/60 = 30

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3 years ago

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Is 1,2,3,4 a geometric sequence ?

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4 years ago

What is the average rate of change from x= 0 to x=5? a. -80 b. -40 c. -8 d. -2

Korvikt [17]

Answer:

-8.

Step-by-step explanation:

That would be change in height divided by change in time:

= (40 - 80) / (5 - 0)

= -40 / 5

= -8.

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4 years ago

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Someone help I don't know what the diameter or radius is

Elenna [48]

<h3>Answer:</h3>

52.38 inch² & 261.90 inch²

<h3>Step-by-step explanation:</h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

$\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }$

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

=> Area = ∅/ 360° × π r²

=> Area = 60°/360° × 22/7 × (10in.)²

=> Area = 1/6 * 22/7 * 100 in²

=> Area = 52 .380 in²

<h3>★ Hence the area of the red sector is 52.38 inch².</h3>

_________________________________

Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .

=> Area = 300/360 × 22/7 × 100 in²

=> Area = 261. 90 in²

<h3>★ Hence the area of blue sector is 261.90 inch².</h3>

$\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}$

$\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}$

5 0

3 years ago

The total cost of hiring Paul the plumber is a function of the card number of hours needed to complete the repair. Paul charges

nasty-shy [4]

Answer:

A y = 40x + 75

B 1 hour = 115

2 hour = 155

3 hour = 195

4 hour = 235

5 hour = 275

6 hour = 315

C, D, E look at pic below

plz mark brainliest

3 0

4 years ago