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JulijaS [17]
3 years ago
14

A honey bee has a mass of 100 mg. How many bees would you need for a mass of 3 kg?

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
5 0

Answer:

you need 3000000 bees

Step-by-step explanation:

1kg=1000000mg.

1000000x3=3000000

hope this helps, have a good day :)

Lady bird [3.3K]3 years ago
3 0
You’ll need 30,000 honey bees
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Write an equation. Then solve the problem. Arturo built 3 sandcastles with 6 towers each. Paco built 5 sandcastles with 4 towers
vlabodo [156]
To get the answer we have to find number of towers.
If Arturo built 3 sandcastles with 6 towers each we can say that Arturo built
3*6=18 towers
If Paco built 5 sandcastles with 4 towers each we can say that Paco built
5*4=20 towers
20-18=2 - difference between Paco and Arturo
Answer:Arturo made more towers. The difference is 2.
8 0
3 years ago
What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

5 0
3 years ago
Algebra 2- Common Functions PLEASE HELP!
RoseWind [281]

Answer: B

Step-by-step explanation:

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==> not A

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Answer B

7 0
3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description. 2m2 + 3 = m double root real and
Jlenok [28]

Answer:

The roots of the equation 2m²+3=m are non-real roots.

Step-by-step explanation:

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2m²+3=m

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a = 2, b = -1, c = 3

Discriminant of an equation is given as:

D = b²-4ac

= (-1)²-4(2)(3)

= 1 - 21

= -20

Discriminant can tell what kinds of roots the equation have.

In our case, the discriminant is less than 0.

When D < 0, the roots of the equation are complex conjugates.(non-real)

8 0
3 years ago
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What does x equal ???​
Orlov [11]

Answer:

x = 107

Step-by-step explanation:

x and 107  are alternate interior angles and alternate interior angles are equal

so x= 107

4 0
3 years ago
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