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igomit [66]
3 years ago
14

What is the perimeter of the figure

Mathematics
2 answers:
Pavel [41]3 years ago
6 0

(23 x 2) + 22.7

46 + 22.7

68.7

Fofino [41]3 years ago
5 0

Answer:

Step-by-step explanation:

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How many seconds are there in a month of 30 days express it in scientific notation​
Evgesh-ka [11]
Answer: 2.592 x 10^6 seconds

Explanation:

There are 3600s in 1 hr

And 24hrs in 1 day which mean

There are 3600 x 24 = 86400s in 1 day

And one month = 30 days

86400 x 30 = 2, 592, 000s in 1 month

Write in scientific notation:

2, 592, 000 = 2.592 x 10^6

6 0
2 years ago
Anybody know the right answer?
Dmitry_Shevchenko [17]

If we just have

y = \cos x

that's an amplitude of 1 and a period of 2\pi

Let's modify this step by step.

Amplitude of 4. Four times the amplitude means a factor of 4 on the outside.

y = 4 \cos x

Period of π. Double the period means a factor of 2 on the inside.

y = 4 \cos(2x)

Horizontal shift of π/2 to the left. To the left means adding a positive number to x. The question appear ambiguous. It's not clear to me if we add to x or 2x; let's make it

y = 4 \cos(2(x + \frac \pi 2))

Vertical shift of 3:

y = 3 + 4 \cos(2(x + \frac \pi 2))

y = 3 + 4 \cos(2x +  \pi)

Depending on the interpretation of the phase shift, that pi may be a pi/2.

Answer: 3 + 4 \cos(2x +  \pi)

4 0
3 years ago
Whats the value of d ?
Ilia_Sergeevich [38]

Hope this helps

Answer: I think 66

Step-by-step explanation:

40 + 26 = 66

8 0
2 years ago
Read 2 more answers
What number id 0.4% is 20
d1i1m1o1n [39]

0.4% x 20 = 0.08


Hope helps!-Aparri

6 0
2 years ago
A machine lifts up containers of coal from the mine and lowers empty containers down. The machine uses an electric motor connect
Shkiper50 [21]

Answer:

The maximum power available to the motor is 2.4 MW

Step-by-step explanation:

The power of  a circuit that has a current, I, and a voltage, V, is given by the relation

Electrical power, P = I²R = I× I×R = I × V

Therefore given that the parameters are;

Voltage in the d.c. power supply = 600 V d.c.

Maximum current in the motor = 4000 A

Therefore, we can find the power as follows;

Maximum motor power = Voltage × Current

The maximum motor power, P available =  600 V × 4000 A = 2400000 W which on converting to MW becomes;

The maximum power available to the motor , P = 2.4 MW.

4 0
3 years ago
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